If you're the type who forgets to put the radix in when you call parseInt, you can use parseFloat and round it however you like. Or, if you're going to be using Math.floor several times: var floor = Math.floor If your string is or might be a float and you want an integer: var x = Math.floor('1000.01') // floor() automatically converts string to number If your string is already in the form of an integer: var x = +'1000' So you get a decimal number even with a leading 0 and an old browser () parseInt() var x = parseInt('1000', 10) // You want to use radix 10 If that doesn't work for you, then there are the parseInt, unary plus, parseFloat with floor, and Math.round methods. I hope you find it useful.The simplest way would be to use the native Number function: var x = Number('1000') To convert an integer to a string, use the built-in str() function. Num_octal_str = f'' # '144' ConclusionĬonverting string to int in Python is easy with the built-in int() function: int('300') # 300 The number systems into which you can convert an integer are binary, hexadecimal, and octal. For example, let’s convert a binary integer 0011 to a string that represents a regular integer: bin = 0b0011īut if you want to represent an integer as a string in another number system, use the f-string formatting. The str() function is clever enough to tell that a binary literal is passed into it. But if you are dealing with other numeric systems, read along.

You can convert an integer to a string using the built-in str() function. To make it complete, let’s turn things around and convert integers back to strings. You now know how to convert a string into an integer in Python. To convert a hexadecimal string to an int, let the int() function know you’re dealing with a 16-base system: int('0圆F', base=16) # '111' When you use the int() function to convert a string to an int, you can specify the number system as the second argument. There is an easy way to fix this problem. This ValueError says that the string you tried to convert is not a valid decimal integer.

Outcome: ValueError: invalid literal for int() with base 10: '0圆F' If you pass for example a hexadecimal string into the int() function, you see an error: int('0圆F') Using int() to convert a string to an integer assumes that a string represents a decimal integer (a 10-base number). Output: 80129553 How to Convert Number Strings in Different Bases Then convert the result to an int using the int() function: big_num_str = '80,129,553'īig_num_int = int(big_num_str.replace(',', '')) 1,000,000) to an int in Python, first, get rid of the commas with the replace() method. To convert a comma-separated number string (e.g.

Num_int = int(num_str) How to Convert Comma-Separated Number String to Int? Converting string to int in Python is easy using the built-in int() function.įor example, let’s convert the string “ 100” to an integer: num_str = '100'

Convert string to int